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(D) The power radiated by a linear antenna is given by the formula $P \propto (L/\lambda)^2$, where $L$ is the length of the antenna and $\lambda$ is

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$9: 16$

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(D) The power radiated by a linear antenna is given by the formula $P \propto (L/\lambda)^2$, where $L$ is the length of the antenna and $\lambda$ is the wavelength of the radiation.Given the ratio of lengths $L_1 : L_2 = 2 : 3$ and the ratio of wavelengths $\lambda_1 : \lambda_2 = 8 : 9$.The ratio of powers is given by:$\frac{P_1}{P_2} = \left( \frac{L_1}{L_2} ight)^2 	imes \left( \frac{\lambda_2}{\lambda_1} ight)^2$Substituting the given values:$\frac{P_1}{P_2} = \left( \frac{2}{3} ight)^2 	imes \left( \frac{9}{8} ight)^2$$\frac{P_1}{P_2} = \frac{4}{9} 	imes \frac{81}{64}$$\frac{P_1}{P_2} = \frac{1}{1} 	imes \frac{9}{16} = \frac{9}{16}$Therefore, the ratio of effective powers radiated is $9: 16$.

If two linear antennas having lengths in the ratio $2: 3$ are emitting radiation of wavelengths in the ratio $8: 9$, then the ratio of effective powers radiated by them are in the ratio

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