If two smallest squares are chosen at random on a chessboard, then the probability of choosing these squares such that they do not have a side in common is:

  • A
    $\frac{1}{18}$
  • B
    $\frac{5}{36}$
  • C
    $\frac{17}{18}$
  • D
    $\frac{7}{36}$

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If $E_1, E_2, \ldots, E_n$ are independent events such that $P(E_r) = \frac{1}{1+r}$ for $r = 1, 2, \ldots, n$, then the probability that at least one of $E_1, E_2, \ldots, E_n$ happens is

Consider the $6 \times 6$ square grid in the figure. Let $A_1, A_2, \ldots, A_{49}$ be the points of intersection (dots in the picture) in some order. We say that $A_i$ and $A_j$ are friends if they are adjacent along a row or along a column. Assume that each point $A_i$ has an equal chance of being chosen.
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