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(A) In the phenomenon of interference, the intensity of light is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$, where $I_1$ and $I_2$ are the i

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there is some intensity of light in the region of destructive interference.

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(A) In the phenomenon of interference, the intensity of light is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$, where $I_1$ and $I_2$ are the intensities of the two waves.Since $I \propto A^2$, where $A$ is the amplitude, the intensities at the points of destructive interference are given by $I_{min} = (\sqrt{I_1} - \sqrt{I_2})^2 = (A_1 - A_2)^2$.If the amplitudes $A_1$ and $A_2$ are different, then $(A_1 - A_2)^2 
eq 0$.Therefore, the intensity at the region of destructive interference is not zero, meaning there is some residual intensity of light.

If two sources of light emit waves of different amplitudes and interfere, then:

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