If two vertices of a triangle are (6, 4) and | vedclass

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(A) The centroid $(G)$ of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by $G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac

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$(4, 8)$

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(A) The centroid $(G)$ of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by $G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right)$.Given vertices are $(6, 4)$ and $(2, 6)$,and centroid is $(4, 6)$.Let the third vertex be $(x_3, y_3)$.Then,$4 = \frac{6 + 2 + x_3}{3}$ $\Rightarrow 12 = 8 + x_3$ $\Rightarrow x_3 = 4$.And,$6 = \frac{4 + 6 + y_3}{3}$ $\Rightarrow 18 = 10 + y_3$ $\Rightarrow y_3 = 8$.Therefore,the third vertex is $(4, 8)$.

If two vertices of a triangle are $(6, 4)$ and $(2, 6)$ and its centroid is $(4, 6)$,then the third vertex is

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