If we multiply a fraction by itself and divide the product by its reciprocal,the fraction thus obtained is $18 \frac{26}{27}$. The original fraction is

  • A
    $\frac{8}{27}$
  • B
    $2 \frac{2}{3}$
  • C
    $1 \frac{2}{3}$
  • D
    None of these

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$\left(\frac{24}{9}\right)^{2} \times \frac{399}{39} \div \frac{41}{899} = ?$

If the numbers $\frac{3}{5}, \frac{2}{3}, \frac{3}{4}$ are given,then we can say that

$\left\{7 \frac{1}{2} + \frac{1}{2} \div \frac{1}{2} \text{ of } \frac{1}{4} - \frac{2}{5} \times 2 \frac{1}{3} \div 1 \frac{7}{8} \text{ of } \left(1 \frac{2}{5} - 1 \frac{1}{3}\right)\right\} = ?$

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The least number to be subtracted from $16800$ to make it a perfect square is

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