If ₹ 1000 is invested at an interest rate of | vedclass

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(A) The interest earned in $10$ years on ₹ $1000$ at $5 \%$ per annum is:$I_1 = \frac{P 	imes R 	imes T}{100} = \frac{1000 	imes 5 	imes 10}{100}

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$16 \frac{2}{3}$ years

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(A) The interest earned in $10$ years on ₹ $1000$ at $5 \%$ per annum is:$I_1 = \frac{P 	imes R 	imes T}{100} = \frac{1000 	imes 5 	imes 10}{100} = ₹ 500$The principal now becomes $P_2 = 1000 + 500 = ₹ 1500$.We now find the time $T_2$ in which ₹ $1500$ becomes ₹ $2000$ at $5 \%$ per annum:$I_2 = A - P_2 = 2000 - 1500 = ₹ 500$$T_2 = \frac{100 	imes I_2}{R 	imes P_2} = \frac{100 	imes 500}{5 	imes 1500} = \frac{100}{15} = 6 \frac{2}{3}$ years.Total time = $10 + 6 \frac{2}{3} = 16 \frac{2}{3}$ years.

If ₹ $1000$ is invested at an interest rate of $5 \%$ and the interest is added to the principal every $10$ years,then the number of years in which it will amount to ₹ $2000$ is:

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