Toluene xrightarrow[{heat}]{{NBS,/,CCl_4}} A | vedclass

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(D) Step $1$: Toluene reacts with $NBS$ in the presence of $CCl_4$ and heat to undergo free-radical bromination at the benzylic position,forming benzy

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$C_6H_5CH_2OCH_3$

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(D) Step $1$: Toluene reacts with $NBS$ in the presence of $CCl_4$ and heat to undergo free-radical bromination at the benzylic position,forming benzyl bromide $(A = C_6H_5CH_2Br)$.Step $2$: Benzyl bromide $(A)$ reacts with sodium methoxide $(CH_3ONa)$,which is a strong nucleophile,via an $S_N2$ mechanism to form benzyl methyl ether $(B = C_6H_5CH_2OCH_3)$.

Toluene $\xrightarrow[{heat}]{{NBS\,/\,CCl_4}} A$ $\xrightarrow{{CH_3ONa}} B,$
The final product $(B)$ formed in the reaction sequence is:

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Toluene $\xrightarrow[{heat}]{{NBS\,/\,CCl_4}} A$ $\xrightarrow{{CH_3ONa}} B,$The final product $(B)$ formed in the reaction sequence is: