In an L-C-R series circuit,if V,V_R,V_L,and V | vedclass

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(A) In an $L-C-R$ series circuit,the current $I$ is the same through all components. The voltage across the resistor $V_R$ is in phase with the curren

Vedclass · Accepted Answer

$V = \sqrt {V_R^2 + {{\left( {{V_L} - {V_C}} \right)}^2}} $

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(A) In an $L-C-R$ series circuit,the current $I$ is the same through all components. The voltage across the resistor $V_R$ is in phase with the current $I$. The voltage across the inductor $V_L$ leads the current by $90^\circ$ (or $\pi/2$ radians). The voltage across the capacitor $V_C$ lags behind the current by $90^\circ$ (or $\pi/2$ radians). Using phasor addition,the resultant voltage $V$ is given by the vector sum of these voltages: $V = \sqrt{V_R^2 + (V_L - V_C)^2}$ This is because $V_L$ and $V_C$ are in opposite directions along the vertical axis,while $V_R$ is along the horizontal axis.

In an $L-C-R$ series circuit,if $V$,$V_R$,$V_L$,and $V_C$ are the voltages across the source,resistor,inductor,and capacitor respectively at any instant,choose the correct relation.

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