In $CsCl$ lattice,the coordination number of $Cs^{+}$ ion is:

$A$ crystal is formed by two elements $X$ and $Y$ in a cubic structure. $X$ atoms are at the corners of a cube,while $Y$ atoms are at the face centers. The formula of the compound will be:

What is the number of atoms present in the unit cells of a simple cubic,body-centered cubic,and face-centered cubic lattice of a monoatomic substance,respectively?

In a cubic structure,$W$ atoms are present at the corners of the unit cell,$O$ atoms are at the edge centers,and $Na$ atoms are at the center of the cube. What is the formula of the compound?

An element has a body-centered cubic $(BCC)$ structure with an edge length of $288 \ pm$. The density of the element is $7.2 \ g/cm^3$. How many atoms are present in $208 \ g$ of the element?

An element has a $bcc$ structure with $12.08 \times 10^{23}$ unit cells. What is the total number of atoms in these unit cells?