In Delta PQR,P-X-Q,P-Y-R and overline{XY} par | vedclass

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(B) Given that in $\Delta PQR$,$\overline{XY} \parallel \overline{QR}$.According to the Basic Proportionality Theorem (Thales Theorem),if a line is dr

Vedclass · Accepted Answer

$7$

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(B) Given that in $\Delta PQR$,$\overline{XY} \parallel \overline{QR}$.According to the Basic Proportionality Theorem (Thales Theorem),if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points,then the other two sides are divided in the same ratio.Therefore,$\frac{PX}{XQ} = \frac{PY}{YR}$.We are given $PX = 3$ and $PQ = 8$. Since $P-X-Q$,we have $XQ = PQ - PX = 8 - 3 = 5$.Now,substitute the values into the ratio: $\frac{3}{5} = \frac{4.2}{YR}$.By cross-multiplying,we get $3 	imes YR = 5 	imes 4.2$.$3 	imes YR = 21$.$YR = \frac{21}{3} = 7$.Thus,the length of $YR$ is $7$.

In $\Delta PQR$,$P-X-Q$,$P-Y-R$ and $\overline{XY} \parallel \overline{QR}$. If $PX = 3$,$PQ = 8$ and $PY = 4.2$,find $YR$.

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