In Delta ABC,m angle B = 90^{circ} and m angl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In $\Delta ABC$,the sum of angles is $180^{\circ}$.Since $m \angle B = 90^{\circ}$ and $m \angle C = 30^{\circ}$,we have $m \angle A = 180^{\circ}

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) In $\Delta ABC$,the sum of angles is $180^{\circ}$.Since $m \angle B = 90^{\circ}$ and $m \angle C = 30^{\circ}$,we have $m \angle A = 180^{\circ} - (90^{\circ} + 30^{\circ}) = 60^{\circ}$.This is a $30^{\circ}-60^{\circ}-90^{\circ}$ triangle.In a $30^{\circ}-60^{\circ}-90^{\circ}$ triangle,the side opposite to the $30^{\circ}$ angle is half the hypotenuse.The side opposite to $30^{\circ}$ is $AB$.The hypotenuse is $AC = 10$.Therefore,$AB = \frac{1}{2} 	imes AC = \frac{1}{2} 	imes 10 = 5$.

In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $m \angle C = 30^{\circ}$. If $AC = 10$,then $AB = \ldots$

Similar Questions

In a right triangle,if the measure of one of the angles is $45^{\circ}$,then the measure of the side opposite to the angle with measure $45^{\circ}$ is $\ldots \ldots \ldots$ times the measure of the hypotenuse.

If $\sec \theta = 1$,then $\theta = \ldots \ldots \ldots$ (in $^{\circ}$)

If $\operatorname{cosec} \theta = \frac{2}{\sqrt{3}}$,then $\theta = \ldots$ (in $^\circ$)

In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $m \angle A = 60^{\circ}$. If $AC = 10$,then $AB = \dots$

In a right triangle,if the length of the hypotenuse is $12$ and the measure of one of the angles is $30^{\circ}$,then the measure of the side opposite to the angle is $\ldots \ldots \ldots \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module