In Delta ABC,AB = AC. If angle A = 50^{circ}, | vedclass

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Question

(A) In $\Delta ABC$,we are given that $AB = AC$. Since the sides opposite to equal angles are equal,the angles opposite to equal sides are also equal.

Vedclass · Accepted Answer

$\angle B = 65^{\circ}, \angle C = 65^{\circ}$

Vedclass · Answer

(A) In $\Delta ABC$,we are given that $AB = AC$. Since the sides opposite to equal angles are equal,the angles opposite to equal sides are also equal. Therefore,$\angle B = \angle C$. By the angle sum property of a triangle,the sum of all interior angles is $180^{\circ}$. So,$\angle A + \angle B + \angle C = 180^{\circ}$. Given $\angle A = 50^{\circ}$,we have $50^{\circ} + \angle B + \angle B = 180^{\circ}$. $2 \angle B = 180^{\circ} - 50^{\circ} = 130^{\circ}$. $\angle B = 130^{\circ} / 2 = 65^{\circ}$. Since $\angle B = \angle C$,we have $\angle C = 65^{\circ}$.

In $\Delta ABC$,$AB = AC$. If $\angle A = 50^{\circ}$,then find $\angle B$ and $\angle C$.

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