In Delta PQR,PQ = PR. If angle Q = 48^{circ}, | vedclass

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Question

(A) Given that in $\Delta PQR$,$PQ = PR$. Since the sides opposite to equal angles are equal,and sides $PQ$ and $PR$ are equal,the angles opposite to

Vedclass · Accepted Answer

$\angle P = 84^{\circ}, \angle R = 48^{\circ}$

Vedclass · Answer

(A) Given that in $\Delta PQR$,$PQ = PR$. Since the sides opposite to equal angles are equal,and sides $PQ$ and $PR$ are equal,the angles opposite to these sides must be equal. Therefore,$\angle R = \angle Q$. Given $\angle Q = 48^{\circ}$,so $\angle R = 48^{\circ}$. In any triangle,the sum of all interior angles is $180^{\circ}$. Thus,$\angle P + \angle Q + \angle R = 180^{\circ}$. Substituting the values: $\angle P + 48^{\circ} + 48^{\circ} = 180^{\circ}$. $\angle P + 96^{\circ} = 180^{\circ}$. $\angle P = 180^{\circ} - 96^{\circ} = 84^{\circ}$. Hence,$\angle P = 84^{\circ}$ and $\angle R = 48^{\circ}$.

In $\Delta PQR$,$PQ = PR$. If $\angle Q = 48^{\circ}$,then find $\angle P$ and $\angle R$.

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