In $\Delta ABC$,$\angle B = 90^{\circ}$,$AB = 6.3 \, cm$,and $BC = 8.4 \, cm$. If the triangle is revolved about the side $AB$,find the volume of the cone so obtained. Similarly,if the triangle $ABC$ is revolved about the side $BC$,find the volume of the cone so obtained.

(N/A) When $\Delta ABC$ is revolved about side $AB$,the height of the cone $h = AB = 6.3 \, cm$ and the radius $r = BC = 8.4 \, cm$. The volume $V_1 = \frac{1}{3} \pi r^2 h = \frac{1}{3} \times \frac{22}{7} \times (8.4)^2 \times 6.3 = 465.696 \, cm^3$. When $\Delta ABC$ is revolved about side $BC$,the height of the cone $h = BC = 8.4 \, cm$ and the radius $r = AB = 6.3 \, cm$. The volume $V_2 = \frac{1}{3} \pi r^2 h = \frac{1}{3} \times \frac{22}{7} \times (6.3)^2 \times 8.4 = 349.272 \, cm^3$.