In Delta ABC and Delta XYZ,mangle A = mangle | vedclass

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(D) In $\Delta ABC$ and $\Delta XYZ$,we are given $m\angle A = m\angle X$ and $m\angle B = m\angle Y$.By the $AA$ (Angle-Angle) similarity criterion,$

Vedclass · Accepted Answer

$10.8$

Vedclass · Answer

(D) In $\Delta ABC$ and $\Delta XYZ$,we are given $m\angle A = m\angle X$ and $m\angle B = m\angle Y$.By the $AA$ (Angle-Angle) similarity criterion,$\Delta ABC \sim \Delta XYZ$.Since the triangles are similar,the ratios of their corresponding sides are equal:$\frac{AB}{XY} = \frac{AC}{XZ} = \frac{BC}{YZ}$.Given $\frac{AB}{XY} = \frac{2}{3}$ and $AC = 7.2$,we substitute these values into the ratio:$\frac{2}{3} = \frac{7.2}{XZ}$.Cross-multiplying to solve for $XZ$:$2 	imes XZ = 7.2 	imes 3$.$2 	imes XZ = 21.6$.$XZ = \frac{21.6}{2} = 10.8$.

In $\Delta ABC$ and $\Delta XYZ$,$m\angle A = m\angle X$,$m\angle B = m\angle Y$ and $\frac{AB}{XY} = \frac{2}{3}$. If $AC = 7.2$,then $XZ = \ldots$

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