In Pb_3O_4, the different oxidation states of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $Pb_3O_4$ is a mixed oxide, which can be represented as $2PbO \cdot PbO_2$. In $PbO$, the oxidation state of $Pb$ is $+2$. In $PbO_2$, the oxidati

Vedclass · Accepted Answer

$2$ and $4$

Vedclass · Answer

(C) $Pb_3O_4$ is a mixed oxide, which can be represented as $2PbO \cdot PbO_2$. In $PbO$, the oxidation state of $Pb$ is $+2$. In $PbO_2$, the oxidation state of $Pb$ is $+4$. Calculation for $PbO$: $x + (-2) = 0 \Rightarrow x = +2$. Calculation for $PbO_2$: $x + 2(-2) = 0$ $\Rightarrow x - 4 = 0$ $\Rightarrow x = +4$. Thus, the oxidation states of $Pb$ in $Pb_3O_4$ are $+2$ and $+4$.

In $Pb_3O_4$, the different oxidation states of $Pb$ are:

Similar Questions

The order of the oxidation state of the phosphorus atom in $H_3PO_2$,$H_3PO_4$,$H_3PO_3$,and $H_4P_2O_6$ is:

What is the oxidation state of oxygen in $O_2^{2-}$ ion?

The oxidation states of sulphur in $S_8$,$S_2F_2$,and $H_2S$ respectively,are:

When ammonium nitrate is heated rapidly,an oxide of nitrogen is formed. What is the oxidation state of nitrogen in this oxide?

What is the change in the oxidation state of nitrogen when $HNO_3$ is converted into $N_2O$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module