In CuSO_4 solution,when an electric current e | vedclass

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(D) According to Faraday's first law of electrolysis,the amount of substance deposited at an electrode is directly proportional to the quantity of ele

Vedclass · Accepted Answer

$2.5$

Vedclass · Answer

(D) According to Faraday's first law of electrolysis,the amount of substance deposited at an electrode is directly proportional to the quantity of electricity passed through the electrolyte. Mathematically,the number of $gm$ equivalents deposited is equal to the number of faradays of electricity passed. Since $1 \ F$ of electricity deposits $1 \ gm$ equivalent of a substance,passing $2.5 \ F$ of electricity will deposit $2.5 \ gm$ equivalents of copper at the cathode. Therefore,the correct option is $(D)$.

In $CuSO_4$ solution,when an electric current equal to $2.5 \ F$ (faraday) is passed,the number of $gm$ equivalents deposited on the cathode is:

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