In an $L-C-R$ series $AC$ circuit,the voltage across each of the components $L, C$,and $R$ is $50\,V$. The voltage across the $L-R$ combination will be

  • A
    $50\,V$
  • B
    $50\sqrt{2}\,V$
  • C
    $100\,V$
  • D
    $0\,V$

Explore More

Similar Questions

$A$ sinusoidal voltage of peak value $283\,V$ and frequency $50\,Hz$ is applied to a series $LCR$ circuit in which $R = 3\,\Omega$,$L = 25.48\,mH$,and $C = 796\,\mu F$. Find the impedance of the circuit in $\Omega$.

If the power factor is $1/2$ in a series $RL$ circuit with $R = 100\,\Omega$ connected to an $ac$ mains $(50\,Hz)$,find the value of $L$.

$A$ light bulb and an inductor coil are connected to an $AC$ source through a key as shown in the figure below. The key is closed and after some time an iron rod is inserted into the interior of the inductor. The glow of the light bulb

An inductor of reactance $1 \Omega$ and a resistor of resistance $3 \Omega$ are connected in series to the terminals of a $10 \ V$ (rms) $AC$ source. The power dissipated in the circuit is (in $W$)

For a series $LCR$ circuit,$R = X_L = 2X_C$. The impedance of the circuit and the phase difference between $V$ and $i$ will be:

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo