In a Delta ABC, if a = 2x, b = 2y and angle C | vedclass

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(B) The area of a triangle is given by the formula $\Delta = \frac{1}{2}ab \sin C.$Given $a = 2x,$ $b = 2y,$ and $\angle C = 120^\circ.$Substituting t

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$xy\sqrt{3}$

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(B) The area of a triangle is given by the formula $\Delta = \frac{1}{2}ab \sin C.$Given $a = 2x,$ $b = 2y,$ and $\angle C = 120^\circ.$Substituting these values into the formula:$\Delta = \frac{1}{2} 	imes (2x) 	imes (2y) 	imes \sin(120^\circ)$Since $\sin(120^\circ) = \sin(180^\circ - 60^\circ) = \sin(60^\circ) = \frac{\sqrt{3}}{2},$$\Delta = \frac{1}{2} 	imes 4xy 	imes \frac{\sqrt{3}}{2}$$\Delta = 2xy 	imes \frac{\sqrt{3}}{2} = xy\sqrt{3}.$

In a $\Delta ABC,$ if $a = 2x,$ $b = 2y$ and $\angle C = 120^\circ,$ then the area of the triangle is

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