(D) Given in $\triangle ABC$: $a=26, b=30, \cos C=\frac{63}{65}$. Using the Law of Cosines: $\cos C = \frac{a^2+b^2-c^2}{2ab}$ $\frac{63}{65} = \frac{

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(D) Given in $\triangle ABC$: $a=26, b=30, \cos C=\frac{63}{65}$. Using the Law of Cosines: $\cos C = \frac{a^2+b^2-c^2}{2ab}$ $\frac{63}{65} = \frac{26^2+30^2-c^2}{2 \times 26 \times 30}$ $\frac{63}{65} = \frac{676+900-c^2}{1560}$ $c^2 = 1576 - \frac{63 \times 1560}{65}$ $c^2 = 1576 - (63 \times 24)$ $c^2 = 1576 - 1512 = 64$ $c = \sqrt{64} = 8$.

Class 11 Mathematics Trigonometrical Equations Relation between sides and angles, Solutions of triangles

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In a $\triangle ABC$,if $a=26, b=30$,and $\cos C=\frac{63}{65}$,then $c=$

AP EAMCET 2024 All AP EAMCET

A
$2$
B
$4$
C
$6$
D
$8$

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Relation between sides and angles, Solutions of triangles

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