In a biprism experiment,the fringe width is 0 | vedclass

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(C) The position of the $n^{th}$ bright fringe is given by $x_n = n \beta$,where $\beta$ is the fringe width.For the $8^{th}$ bright fringe $(n=8)$: $

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$1.5$

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(C) The position of the $n^{th}$ bright fringe is given by $x_n = n \beta$,where $\beta$ is the fringe width.For the $8^{th}$ bright fringe $(n=8)$: $x_8 = 8 \beta = 8 	imes 0.6 \ mm = 4.8 \ mm$.The position of the $n^{th}$ dark fringe is given by $x'_n = (n - 0.5) \beta$.For the $6^{th}$ dark fringe $(n=6)$: $x'_6 = (6 - 0.5) \beta = 5.5 \beta = 5.5 	imes 0.6 \ mm = 3.3 \ mm$.The distance between the $8^{th}$ bright fringe and the $6^{th}$ dark fringe is $\Delta x = x_8 - x'_6 = 4.8 \ mm - 3.3 \ mm = 1.5 \ mm$.

In a biprism experiment,the fringe width is $0.6 \ mm$. The distance between the $6^{th}$ dark fringe and the $8^{th}$ bright fringe on the same side of the central bright fringe is: (in $mm$)

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