In a capillary tube having area of cross-section $A$,the water rises to a height $h$. If the cross-sectional area is reduced to $\frac{A}{9}$,the rise of water in the capillary tube is

  • A
    $4 h$
  • B
    $3 h$
  • C
    $2 h$
  • D
    $h$

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