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(B) rear-view mirror is a convex mirror.Given: Radius of curvature $R = 1.50 \, m$,Object distance $u = -10.0 \, m$.The focal length $f = \frac{R}{2}

Vedclass · Accepted Answer

$0.07$

Vedclass · Answer

(B) rear-view mirror is a convex mirror.Given: Radius of curvature $R = 1.50 \, m$,Object distance $u = -10.0 \, m$.The focal length $f = \frac{R}{2} = \frac{1.5}{2} = 0.75 \, m$.Using the mirror formula: $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{0.75} - \frac{1}{-10} = \frac{4}{3} + \frac{1}{10} = \frac{40 + 3}{30} = \frac{43}{30}$.Thus,$v = \frac{30}{43} \, m$.The magnification $m$ is given by $m = -\frac{v}{u}$.$m = -\frac{(30/43)}{-10} = \frac{30}{430} = \frac{3}{43} \approx 0.0697$.Rounding to two decimal places,the magnification factor is approximately $0.07$.

In a car,a rear-view mirror having a radius of curvature $1.50 \, m$ forms a virtual image of a bus located $10.0 \, m$ from the mirror. The factor by which the mirror magnifies the size of the bus is close to

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