In a certain code CREAM is written as NBDBQ. | vedclass

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(C) To solve this,let's analyze the pattern in $CREAM$ to $NBDBQ$:$C (+1) = D$$R (+1) = S$$E (+1) = F$$A (+1) = B$$M (+1) = N$Reversing the sequence $

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$BEDQA$

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(C) To solve this,let's analyze the pattern in $CREAM$ to $NBDBQ$:$C (+1) = D$$R (+1) = S$$E (+1) = F$$A (+1) = B$$M (+1) = N$Reversing the sequence $DSFBN$ gives $NBFSD$. However,let's look at the mapping directly:$C \rightarrow B (-1)$$R \rightarrow Q (-1)$$E \rightarrow D (-1)$$A \rightarrow Z (-1)$$M \rightarrow L (-1)$Wait,let's re-examine the given code $NBDBQ$ for $CREAM$:$C \rightarrow N$$R \rightarrow B$$E \rightarrow D$$A \rightarrow B$$M \rightarrow Q$Actually,the pattern is: $C+1=D, R+1=S, E+1=F, A+1=B, M+1=N$. Reversed: $N, B, F, S, D$. This does not match.Let's try: $M+1=N, A+1=B, E-1=D, R-1=Q, C-1=B$. So $M, A, E, R, C$ becomes $N, B, D, Q, B$. Thus,for $BREAD$ $(B, R, E, A, D)$: $D+1=E, A+1=B, E-1=D, R-1=Q, B-1=A$. Result: $EB DQA$.

In a certain code $CREAM$ is written as $NBDBQ$. How is $BREAD$ written in that code?

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