In a certain office,72 % of the workers prefe | vedclass

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(B) Let the total number of workers be $x$.Let $C$ be the set of workers who prefer cold drink and $T$ be the set of workers who prefer tea.Given: $n(

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$250$

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(B) Let the total number of workers be $x$.Let $C$ be the set of workers who prefer cold drink and $T$ be the set of workers who prefer tea.Given: $n(C) = 72 \% 	ext{ of } x$,$n(T) = 44 \% 	ext{ of } x$.Since every worker prefers at least one drink,$n(C \cup T) = 100 \% 	ext{ of } x$.We know that $n(C \cup T) = n(C) + n(T) - n(C \cap T)$.Substituting the values: $100 \% = 72 \% + 44 \% - n(C \cap T) \%$.$100 \% = 116 \% - n(C \cap T) \%$.Therefore,$n(C \cap T) = 116 \% - 100 \% = 16 \%$.It is given that $40$ workers like both,so $16 \% 	ext{ of } x = 40$.$x = \frac{40 	imes 100}{16} = 250$.Thus,the total number of workers is $250$.

In a certain office,$72 \%$ of the workers prefer cold drink and $44 \%$ prefer tea. If each of them prefers cold drink or tea and $40$ like both,then the total number of workers in the office is

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