(A) Given: Radius $r = 8.4 \, cm$,Central angle $\theta = 60^{\circ}$.Area of minor sector = $\frac{\theta}{360^{\circ}} \times \pi r^2 = \frac{60}{36

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) Given: Radius $r = 8.4 \, cm$,Central angle $\theta = 60^{\circ}$.Area of minor sector = $\frac{\theta}{360^{\circ}} \times \pi r^2 = \frac{60}{360} \times \frac{22}{7} \times 8.4 \times 8.4 = \frac{1}{6} \times 22 \times 1.2 \times 8.4 = 36.96 \, cm^2$.Area of circle = $\pi r^2 = \frac{22}{7} \times 8.4 \times 8.4 = 221.76 \, cm^2$.Area of major sector = Area of circle - Area of minor sector = $221.76 - 36.96 = 184.8 \, cm^2$.

Class 10 Mathematics Areas Related to Circles Areas of Sector and Segment of a Circle

Easy

In a circle with radius $8.4 \, cm$,a minor arc subtends an angle of $60^{\circ}$ at the centre. Find the area of the minor sector and the major sector corresponding to this arc.

A
$36.96 \, cm^2, 184.8 \, cm^2$
B
$36.96 \, cm^2, 190.5 \, cm^2$
C
$38.50 \, cm^2, 184.8 \, cm^2$
D
$36.96 \, cm^2, 221.76 \, cm^2$

Explore More

Browse All

Question Bank

All Subjects

Class 10 Questions

Class 10

Mathematics Questions

Chapter

Areas Related to Circles

Subtopic

Areas of Sector and Segment of a Circle

The circumference of a circular ground is $352\, m$. Find the area of the ground (in $m^2$).

Easy

View Solution

In a circle,the ratio of the areas of two distinct minor sectors is $1:4$. Then,the ratio of the angles at the centre for those minor sectors is $\ldots \ldots \ldots \ldots$.

Easy

View Solution

The area of a circular playground is $22176 \, m^{2}$. Find the cost of fencing this ground at the rate of $Rs. \, 50$ per $metre$. (in $Rs.$)

Medium

View Solution

In $\odot(O, r)$,the length of minor $\widehat{ACB}$ is one-eighth of the circumference of the circle. Then,the measure of the angle subtended at the centre by that arc is $\ldots \ldots \ldots \ldots$ (in $^\circ$)

Easy

View Solution

The side length of square $ABCD$ shown in the diagram is $42 \ cm$. The shaded design is formed by drawing semicircles on all the sides of the square. Find the area of the shaded design in $cm^2$.

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

In a circle with radius $8.4 \, cm$,a minor arc subtends an angle of $60^{\circ}$ at the centre. Find the area of the minor sector and the major sector corresponding to this arc.

Similar Questions

The circumference of a circular ground is $352\, m$. Find the area of the ground (in $m^2$).

In a circle,the ratio of the areas of two distinct minor sectors is $1:4$. Then,the ratio of the angles at the centre for those minor sectors is $\ldots \ldots \ldots \ldots$.

The area of a circular playground is $22176 \, m^{2}$. Find the cost of fencing this ground at the rate of $Rs. \, 50$ per $metre$. (in $Rs.$)

In $\odot(O, r)$,the length of minor $\widehat{ACB}$ is one-eighth of the circumference of the circle. Then,the measure of the angle subtended at the centre by that arc is $\ldots \ldots \ldots \ldots$ (in $^\circ$)

The side length of square $ABCD$ shown in the diagram is $42 \ cm$. The shaded design is formed by drawing semicircles on all the sides of the square. Find the area of the shaded design in $cm^2$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module