In a circle with radius $14 \, cm$,$\overline{OA}$ and $\overline{OB}$ are radii perpendicular to each other. Then,the area of the minor sector corresponding to $\angle AOB$ is $\ldots \ldots \ldots \, cm^2$.

  • A
    $616$
  • B
    $308$
  • C
    $154$
  • D
    $77$

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The area of a circle is $200 \, cm^{2}$. Then,the area of a minor sector of that circle can be $\ldots \ldots \ldots \, cm^{2}$.

Area of a sector of angle $p$ (in degrees) of a circle with radius $R$ is

Find the area of the shaded design in the figure where $ABCD$ is a square of side $10 \, cm$ and semicircles are drawn with each side of the square as diameter. (in $cm^2$) (Use $\pi = 3.14$)

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Which of the following correctly matches the information given in Part $I$ and Part $II$?
Part $I$ Part $II$
$1.$ Formula to find the length of a minor arc $a.$ $C=2\pi r$
$2.$ Formula to find the area of a minor sector $b.$ $A=\pi r^{2}$
$3.$ Formula to find the area of a circle $c.$ $l=\frac{\pi r \theta}{180}$
$4.$ Formula to find the circumference of a circle $d.$ $A=\frac{\pi r^{2} \theta}{360}$

Find the area of the segment of a circle of radius $12 \, cm$ whose corresponding sector has a central angle of $60^{\circ}$ (Use $\pi = 3.14$).

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