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(A) The induced $e.m.f.$ $(e)$ in a coil due to self-inductance is given by the formula: $|e| = L \frac{di}{dt}$.Here,the change in current $di = 18 \

Vedclass · Accepted Answer

$62.5$

Vedclass · Answer

(A) The induced $e.m.f.$ $(e)$ in a coil due to self-inductance is given by the formula: $|e| = L \frac{di}{dt}$.Here,the change in current $di = 18 \,A - 2 \,A = 16 \,A$.The time interval $dt = 0.05 \,s$.The induced $e.m.f.$ $|e| = 20 \,V$.Substituting these values into the formula:$20 = L 	imes \frac{16}{0.05}$$20 = L 	imes 320$$L = \frac{20}{320} \,H = \frac{1}{16} \,H = 0.0625 \,H$.To convert the value into $mH$,multiply by $1000$:$L = 0.0625 	imes 1000 \,mH = 62.5 \,mH$.

In a circular conducting coil,when current increases from $2 \,A$ to $18 \,A$ in $0.05 \,s$,the induced $e.m.f.$ is $20 \,V$. The self-inductance of the coil is.....$mH$.

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