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(C) In a close-packed structure,the radius of a tetrahedral void $(r_t)$ is related to the radius of the sphere $(R)$ by the formula $r_t = 0.225R$. T

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(C) In a close-packed structure,the radius of a tetrahedral void $(r_t)$ is related to the radius of the sphere $(R)$ by the formula $r_t = 0.225R$. The radius of an octahedral void $(r_o)$ is related to the radius of the sphere $(R)$ by the formula $r_o = 0.414R$. Comparing the two values,$0.414R > 0.225R$,which means the size of the octahedral void is larger than that of the tetrahedral void.

In a close-packed lattice,how does the size of an octahedral void compare to that of a tetrahedral void?

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