In a college,frac{1}{5} of the girls and frac | vedclass

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Question

(A) Let the number of girls be $x$ and the number of boys be $y$.Total number of students $= x + y$.Number of girls who participated $= \frac{1}{5}x$.

Vedclass · Accepted Answer

$\frac{13}{80}$

Vedclass · Answer

(A) Let the number of girls be $x$ and the number of boys be $y$.Total number of students $= x + y$.Number of girls who participated $= \frac{1}{5}x$.Number of boys who participated $= \frac{1}{8}y$.Total number of students who participated $= \frac{1}{5}x + \frac{1}{8}y = \frac{8x + 5y}{40}$.The fraction of total students who participated is given by $\frac{	ext{Total participants}}{	ext{Total students}} = \frac{\frac{8x + 5y}{40}}{x + y} = \frac{8x + 5y}{40(x + y)}$.Note: Since the ratio of boys to girls is not provided,the exact numerical fraction cannot be determined unless $x = y$. Assuming the question implies an equal number of boys and girls $(x = y)$:$\frac{8x + 5x}{40(x + x)} = \frac{13x}{40(2x)} = \frac{13}{80}$.

In a college,$\frac{1}{5}$ of the girls and $\frac{1}{8}$ of the boys took part in a social camp. The fraction of the total students in the college who took part in the camp is:

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