In a common base mode of a transistor,the collector current is $5.488 \ mA$ for an emitter current of $5.60 \ mA$. The value of the base current amplification factor $(\beta)$ will be

In a common emitter amplifier,a change of $0.2 \text{ mA}$ in the base current causes a change of $5 \text{ mA}$ in the collector current. If the input resistance is $2 \text{ k}\Omega$ and the voltage gain is $75$,what is the load resistance used in the circuit?

If $X, Y$ and $Z$ are the sizes of the emitter,base and collector of a transistor respectively,then

The input resistance of a silicon transistor is $100\,\Omega$. Base current is changed by $40\,\mu A$,which results in a change in collector current by $2\,mA$. This transistor is used as a common emitter amplifier with a load resistance of $4\,k\Omega$. The voltage gain of the amplifier is:

In an $n-p-n$ transistor,in $CE$ configuration:

Consider an amplifier circuit in which a transistor is used in common-emitter mode. The load resistance is $3 k \Omega$. When a signal of $30 mV$ is added to the base-emitter voltage, the base current changes by $30 \mu A$ and the collector current changes by $3 mA$. The power gain in this circuit will be: