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(B) Given: Input resistance $R_{i} = 1000 \Omega$,Input signal voltage $v_{i} = 5 mV = 5 	imes 10^{-3} V$,and current gain $\beta = 60$. First,calcul

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$3 	imes 10^{-4} 	ext{ A}$

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(B) Given: Input resistance $R_{i} = 1000 \Omega$,Input signal voltage $v_{i} = 5 mV = 5 	imes 10^{-3} V$,and current gain $\beta = 60$. First,calculate the input current $I_{b}$ using Ohm's law: $I_{b} = \frac{v_{i}}{R_{i}} = \frac{5 	imes 10^{-3} V}{1000 \Omega} = 5 	imes 10^{-6} A$. The output current in a common emitter amplifier is the collector current $I_{c}$. Using the relation $I_{c} = \beta 	imes I_{b}$,we get: $I_{c} = 60 	imes 5 	imes 10^{-6} A = 300 	imes 10^{-6} A$. Therefore,the peak value of the output current is $3 	imes 10^{-4} A$.

In a common emitter amplifier,the input resistance is $1000 \Omega$,the peak value of the input signal voltage is $5 mV$,and $\beta = 60$. The peak value of the output current is:

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