In a common emitter transistor amplifier,the resistance of the collector is $3 \ k\Omega$. If the current amplification factor is $100$ and the base resistance is $2 \ k\Omega$,then the power gain of the transistor is:

In an $n-p-n$ transistor,in $CE$ configuration:

In an $n-p-n$ transistor circuit,the collector current is $10 \text{ mA}$. If $95\%$ of the electrons emitted reach the collector,then the base current is nearly: (in $mA$)

For a constant collector-emitter voltage of $8\,V$,the collector current of a transistor changed from $4\,mA$ to $6\,mA$,whereas the base current changed from $20\,\mu A$ to $25\,\mu A$. If the transistor is in the active state,the small signal current gain (current amplification factor) will be:

In a transistor amplifier, $AC$ current gain is $64$, the load resistance is $5400 \ \Omega$ and the input resistance of the transistor is $540 \ \Omega$. The voltage gain is

In a transistor,the collector current is always less than the emitter current because: