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(C) Let the total number of workers be $x$.Skilled workers $= 0.75x$.Unskilled workers $= 0.25x$.Permanent skilled workers $= 80\% 	ext{ of } 0.75x =

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$360$

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(C) Let the total number of workers be $x$.Skilled workers $= 0.75x$.Unskilled workers $= 0.25x$.Permanent skilled workers $= 80\% 	ext{ of } 0.75x = 0.80 	imes 0.75x = 0.60x$.Permanent unskilled workers $= 20\% 	ext{ of } 0.25x = 0.20 	imes 0.25x = 0.05x$.Total permanent workers $= 0.60x + 0.05x = 0.65x$.Temporary workers $= 	ext{Total workers} - 	ext{Permanent workers} = x - 0.65x = 0.35x$.Given that the number of temporary workers is $126$,we have:$0.35x = 126$$x = \frac{126}{0.35} = \frac{12600}{35} = 360$.Therefore,the total number of workers is $360$.

In a company,there are $75\%$ skilled workers and the remaining are unskilled. $80\%$ of skilled workers and $20\%$ of unskilled workers are permanent. If the number of temporary workers is $126$,what is the total number of workers?

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