(D) In a unit cell of $AB$, there are $8$ corners occupied by $A$ atoms and $1$ body centre occupied by a $B$ atom.Contribution of $A$ atoms = $8 \tim

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(D) In a unit cell of $AB$, there are $8$ corners occupied by $A$ atoms and $1$ body centre occupied by a $B$ atom.Contribution of $A$ atoms = $8 \times (1/8) = 1$ atom.Contribution of $B$ atoms = $1 \times 1 = 1$ atom.Since $A$ atoms have up-spin and $B$ atoms have down-spin, the magnetic moments cancel each other out.Therefore, the magnetic nature of the compound $AB$ in an isolated unit cell is anti-ferromagnetic.

Class 12 Chemistry Solid State Crystal structure and Coordination number

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In a compound $AB$, $A$ atoms occupy the corners of the cube and the $B$ atoms occupy the body centre of the cube. If the $A$ atoms possess magnetic moment due to up-spin and $B$ atoms possess magnetic moment due to down-spin, the magnetic nature of the compound $AB$ in an isolated unit cell is

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paramagnetic
B
ferrimagnetic
C
diamagnetic
D
anti-ferromagnetic

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In a compound $AB$, $A$ atoms occupy the corners of the cube and the $B$ atoms occupy the body centre of the cube. If the $A$ atoms possess magnetic moment due to up-spin and $B$ atoms possess magnetic moment due to down-spin, the magnetic nature of the compound $AB$ in an isolated unit cell is

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An element has a $bcc$ structure with $12.08 \times 10^{23}$ unit cells. What is the total number of atoms in these unit cells?

The arrangement of $X^{-}$ ions around $A^{+}$ ion in solid $AX$ is given in the figure. If the radius of $X^{-}$ is $250 \ pm$, the radius of $A^{+}$ is: (in $pm$)

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An ionic solid $AB$ crystallizes in a $NaCl$-type structure,where $A$ ions are at the corners of the cube. If all face-centered ions along one axis are removed,then the stoichiometry of the resulting solid will be .....

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