In a conference of 8 persons,if each person s | vedclass

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(D) To find the total number of handshakes,we need to choose $2$ persons out of $8$ to perform one handshake.This is a combination problem because the

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$28$

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(D) To find the total number of handshakes,we need to choose $2$ persons out of $8$ to perform one handshake.This is a combination problem because the order of the two people shaking hands does not matter.The number of ways to choose $2$ persons out of $8$ is given by the combination formula $^nC_r = \frac{n!}{r!(n-r)!}$.Here,$n = 8$ and $r = 2$.Total handshakes = $^8C_2 = \frac{8 	imes 7}{2 	imes 1} = 28$.Therefore,the total number of handshakes is $28$.

In a conference of $8$ persons,if each person shakes hands with every other person exactly once,then the total number of handshakes is:

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