In a copper voltameter,the mass deposited in $6 \text{ min}$ is $m \text{ g}$. If the current-time graph for the voltameter is as shown in the figure,then the $E.C.E.$ of the copper is:

  • A
    $m / 5$
  • B
    $m / 300$
  • C
    $5 m$
  • D
    $m / 18000$

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