In a diffraction pattern produced by a thin w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The fringe width $\beta$ in a diffraction pattern produced by a wire (which acts like a single slit of width $d$) is given by the formula: $\beta

Vedclass · Accepted Answer

Decreases

Vedclass · Answer

(A) The fringe width $\beta$ in a diffraction pattern produced by a wire (which acts like a single slit of width $d$) is given by the formula: $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance of the screen from the wire,and $d$ is the diameter of the wire.From the formula,it is clear that the fringe width $\beta$ is inversely proportional to the diameter of the wire $d$ (i.e.,$\beta \propto \frac{1}{d}$).Therefore,when the diameter $d$ of the wire is increased,the fringe width $\beta$ decreases.

In a diffraction pattern produced by a thin wire,what happens to the fringe width when the diameter of the wire is increased?

Similar Questions

$A$ diffraction pattern is obtained by using a beam of red light. If the red light is replaced by blue light,then:

The condition for obtaining secondary maxima in the diffraction pattern due to a single slit is:

Why does a $DVD$ store almost $30$ times more information than a $CD$?

In a single slit diffraction pattern,the intensity and width of the fringes are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module