In a division sum,the divisor is 4 times the | vedclass

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(D) Given that the divisor is $a$ and the dividend is $b$.According to the problem,the divisor is $4$ times the quotient,so the quotient $= \frac{a}{4

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$\frac{a(a+2)}{b}=4$

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(D) Given that the divisor is $a$ and the dividend is $b$.According to the problem,the divisor is $4$ times the quotient,so the quotient $= \frac{a}{4}$.The divisor is also twice the remainder,so the remainder $= \frac{a}{2}$.Using the division algorithm: $	ext{Dividend} = (	ext{Divisor} 	imes 	ext{Quotient}) + 	ext{Remainder}$.Substituting the values: $b = (a 	imes \frac{a}{4}) + \frac{a}{2}$.$b = \frac{a^2}{4} + \frac{a}{2} = \frac{a^2 + 2a}{4}$.$4b = a^2 + 2a = a(a + 2)$.Therefore,$\frac{a(a+2)}{b} = 4$.

In a division sum,the divisor is $4$ times the quotient and twice the remainder. If $a$ and $b$ are respectively the divisor and the dividend,then

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