In a face centred cubic lattice,atom $A$ occupies the corner positions and atom $B$ occupies the face centre positions. If one atom of $B$ is missing from one of the face centred points,the formula of the compound is:

  • A
    $A_2B$
  • B
    $AB_2$
  • C
    $A_2B_3$
  • D
    $A_2B_5$

Explore More

Similar Questions

The $FCC$ unit cell of a compound contains ions of $A$ at the corners and ions of $B$ at the centre of each face. What is the formula of the compound?

What are two types of crystal structures shown by ice at different pressures?

In the $NaCl$ structure,what is the position of $Cl^-$ ions?

In a face-centered cubic $(FCC)$ unit cell,how many unit cells share an atom located at the face center?

$A$ crystal is made of particles $X$ and $Y$. $X$ forms $fcc$ packing and $Y$ occupies all the octahedral voids. If all the particles along one body diagonal are removed,then the formula of the crystal would be:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo