In a Fraunhofer's diffraction obtained by a single slit aperture,the value of path difference for $n^{th}$ order of minima is

  • A
    $n\lambda$
  • B
    $2n\lambda$
  • C
    $\frac{(2n - 1)\lambda}{2}$
  • D
    $(2n - 1)\lambda$

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Through a narrow slit of width $2 \,mm$, a diffraction pattern is formed on a screen kept at a distance $2 \,m$ from the slit. The wavelength of the light used is $6330 \mathring{A}$ and it falls normal to the slit and screen. Then, the distance between the two minima on either side of the central maximum is (in $\,mm$)

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