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(D) The magnetic field $B$ at the center of a circular current loop is given by the formula: $B = \frac{\mu_0 i}{2r}$.Given values are: $B = 12.56 \,

Vedclass · Accepted Answer

$1.04 	imes 10^{-3} \, A$

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(D) The magnetic field $B$ at the center of a circular current loop is given by the formula: $B = \frac{\mu_0 i}{2r}$.Given values are: $B = 12.56 \, T$,$r = 5.2 	imes 10^{-11} \, m$,and $\mu_0 = 4\pi 	imes 10^{-7} \, T \cdot m/A$.Substituting these values into the formula:$12.56 = \frac{(4\pi 	imes 10^{-7}) 	imes i}{2 	imes 5.2 	imes 10^{-11}}$$12.56 = \frac{2\pi 	imes 10^{-7} 	imes i}{5.2 	imes 10^{-11}}$Using $\pi \approx 3.14$,we have $2\pi \approx 6.28$.$12.56 = \frac{6.28 	imes 10^{-7} 	imes i}{5.2 	imes 10^{-11}}$$i = \frac{12.56 	imes 5.2 	imes 10^{-11}}{6.28 	imes 10^{-7}}$$i = 2 	imes 5.2 	imes 10^{-4} \, A$$i = 10.4 	imes 10^{-4} \, A = 1.04 	imes 10^{-3} \, A$.

In a hydrogen atom,an electron moves in a circular orbit of radius $5.2 \times 10^{-11} \, m$ and produces a magnetic induction of $12.56 \, T$ at its nucleus. The current produced by the motion of the electron will be (Given $\mu_0 = 4\pi \times 10^{-7} \, Wb/A \cdot m$)

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