In a meter bridge experiment,a null point is | vedclass

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(B) In a meter bridge experiment,the condition for the null point is given by the Wheatstone bridge principle: $\frac{P}{Q} = \frac{R_1}{R_2}$,where $

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$l 	ext{ cm}$ from the left end.

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(B) In a meter bridge experiment,the condition for the null point is given by the Wheatstone bridge principle: $\frac{P}{Q} = \frac{R_1}{R_2}$,where $R_1$ and $R_2$ are the resistances of the two segments of the wire.Since $R = ho \frac{L}{A}$,the ratio of the resistances of the two segments is $\frac{R_1}{R_2} = \frac{ho (l/A)}{ho ((100-l)/A)} = \frac{l}{100-l}$.This ratio depends only on the lengths of the segments and is independent of the resistivity $ho$ and the cross-sectional area $A$ of the wire.Therefore,changing the cross-sectional area of the wire does not affect the balance condition.The null point will remain at the same position,i.e.,$l 	ext{ cm}$ from the left end.

In a meter bridge experiment,a null point is obtained at $l \text{ cm}$ from the left end. If the meter bridge wire is replaced by a wire of the same material but twice the area of cross-section,then the null point is obtained at a distance:

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