In a moving coil galvanometer,a strong horse- | vedclass

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(C) In a moving coil galvanometer,the torque acting on the coil is given by $\vec{	au} = \vec{M} 	imes \vec{B}$,which has a magnitude of $	au = MB

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produce a magnetic field which is parallel to the plane of the coil at any position

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(C) In a moving coil galvanometer,the torque acting on the coil is given by $\vec{	au} = \vec{M} 	imes \vec{B}$,which has a magnitude of $	au = MB \sin 	heta$,where $	heta$ is the angle between the magnetic moment $\vec{M}$ and the magnetic field $\vec{B}$.To ensure that the torque is always proportional to the current,we need $\sin 	heta = 1$,which means $	heta = 90^{\circ}$.By using a strong horse-shoe magnet with concave-shaped pole pieces,the magnetic field lines are made radial.In a radial magnetic field,the plane of the coil is always parallel to the magnetic field lines for any orientation of the coil,ensuring $	heta = 90^{\circ}$ at all times.

In a moving coil galvanometer,a strong horse-shoe magnet with concave-shaped pole pieces is used to:

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