In a nuclide, one a.m.u. of mass is dissipate | vedclass

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(B) The mass-energy equivalence is given by Einstein's equation $E = mc^2$. For $1 \ a.m.u.$ (atomic mass unit), the energy equivalent is calculated a

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$931.5 	imes 10^6 \ eV$

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(B) The mass-energy equivalence is given by Einstein's equation $E = mc^2$. For $1 \ a.m.u.$ (atomic mass unit), the energy equivalent is calculated as follows: $1 \ a.m.u. = 1.6605 	imes 10^{-27} \ kg$. Using $c = 2.9979 	imes 10^8 \ m/s$, the energy $E = (1.6605 	imes 10^{-27} \ kg) 	imes (2.9979 	imes 10^8 \ m/s)^2 \approx 1.4924 	imes 10^{-10} \ J$. Since $1 \ eV = 1.6022 	imes 10^{-19} \ J$, then $1 \ MeV = 1.6022 	imes 10^{-13} \ J$. Dividing the energy in Joules by the conversion factor for $MeV$: $E = \frac{1.4924 	imes 10^{-10} \ J}{1.6022 	imes 10^{-13} \ J/MeV} \approx 931.5 \ MeV$. Since $1 \ MeV = 10^6 \ eV$, the energy is $931.5 	imes 10^6 \ eV$.

In a nuclide, one $a.m.u.$ of mass is dissipated into energy to bind its nucleons. The energy equivalent of this mass is

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