In a photoelectric effect experiment,light of frequency $1.5$ times the threshold frequency is made to fall on the surface of a photosensitive material. If the frequency is halved and the intensity is doubled,the number of photoelectrons emitted will be:

In a photoelectric experiment,keeping the frequency of incident radiation and the accelerating potential fixed,if the intensity of incident light is increased,then:

$A$ photosensitive material is at $9\,m$ to the left of the origin and the source of light is at $7\,m$ to the right of the origin along the $x$-axis. The photosensitive material and the source of light start from rest and move,respectively,with $8\widehat{i}\,m/s$ and $4\widehat{i}\,m/s$. The ratio of intensities at $t = 0$ to $t = 3\,s$ as received by the photosensitive material is:

The magnitude of saturation photoelectric current depends upon

Which figure shows the correct variation of applied potential difference $(V)$ with photoelectric current $(I)$ at two different intensities of light $(I_1 < I_2)$ of the same wavelength?

For a given source,with an increase in intensity of incident radiation,the . . . . . .