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Question

(B) According to Einstein's photoelectric equation,the maximum kinetic energy is given by:$(KE)_{\max} = h
u - \phi_0$where $\phi_0 = h
u_0$ is the

Vedclass · Accepted Answer

$\frac{B}{A}$

Vedclass · Answer

(B) According to Einstein's photoelectric equation,the maximum kinetic energy is given by:$(KE)_{\max} = h
u - \phi_0$where $\phi_0 = h
u_0$ is the work function.Comparing this with the equation of a straight line $y = mx + c$:Here,$y = (KE)_{\max}$,$x = 
u$,$m = h$ (slope),and $c = -h
u_0$ (y-intercept).$1$. The $X$-intercept $(A)$ occurs when $(KE)_{\max} = 0$:$0 = h
u - h
u_0 \implies 
u = 
u_0 = A$.$2$. The $Y$-intercept $(B)$ occurs when $
u = 0$:$(KE)_{\max} = -h
u_0 = B$. Since $B$ represents the magnitude of the intercept,we take $|B| = h
u_0$.Therefore,the ratio of the magnitude of the $Y$-intercept to the $X$-intercept is:$\frac{|B|}{A} = \frac{h
u_0}{
u_0} = h$.Thus,Planck's constant $h$ is given by $\frac{B}{A}$ (considering magnitudes).

In a photoelectric experiment,a graph of maximum kinetic energy $(KE_{\max})$ against the frequency of incident radiation $(\nu)$ is plotted. If $A$ and $B$ are the intercepts on the $X$ and $Y$ axis respectively,the Planck's constant is given by:

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