In a potentiometer of 10 wires,the balance po | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The potential drop across the potentiometer wire is given by $V = I \cdot R_{wire} = \frac{E_{main}}{R_{main} + R_{wire}} \cdot R_{wire}$.To shift

Vedclass · Accepted Answer

Increase resistance in the main circuit

Vedclass · Answer

(A) The potential drop across the potentiometer wire is given by $V = I \cdot R_{wire} = \frac{E_{main}}{R_{main} + R_{wire}} \cdot R_{wire}$.To shift the balance point to a higher wire number (greater length),the potential gradient $(x = V/L)$ must be decreased.Since $x = \frac{V}{L} = \frac{I \cdot \rho}{A}$,decreasing the current $I$ in the primary circuit will decrease the potential gradient.By increasing the resistance in the main (primary) circuit,the current $I$ decreases,which reduces the potential gradient.Consequently,a greater length of the wire is required to balance the same emf of the secondary cell.Therefore,we should increase the resistance in the main circuit.

In a potentiometer of $10$ wires,the balance point is obtained on the $6^{\text{th}}$ wire. To shift the balance point to the $8^{\text{th}}$ wire,we should:

Similar Questions

In a potentiometer experiment, a null point is obtained at a particular point for a cell on a potentiometer wire of length '$x$' cm. If the length of the potentiometer wire is increased by a few cm without changing the cell or the driving source, the balancing length will:

In a potentiometer, the area of cross-section of the wire is $4 \, cm^2$, the current flowing in the circuit is $1 \, A$ and the potential gradient is $7.5 \, V/m$, then the resistivity of the potentiometer wire is

$A$ potentiometer wire has length $L$. For a given cell of emf $E$,the balancing length is $\frac{L}{3}$ from the positive end of the wire. If the length of the potentiometer wire is increased by $50 \%$,then for the same cell,the balance point is obtained at length

Vedclass Test Series

Exam Paper Generator

Online Exam Module