In a pure silicon (n_i = 10^{16}/m^3) crystal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given that the intrinsic carrier concentration $n_i = 10^{16}\, m^{-3}$.When phosphorus (a pentavalent impurity) is added to silicon,it creates an

Vedclass · Accepted Answer

$10^{11}\, m^{-3}$

Vedclass · Answer

(C) Given that the intrinsic carrier concentration $n_i = 10^{16}\, m^{-3}$.When phosphorus (a pentavalent impurity) is added to silicon,it creates an $n$-type semiconductor.The concentration of donor atoms added is $N_D = 10^{21}\, m^{-3}$.Since $N_D \gg n_i$,the electron concentration $n_e \approx N_D = 10^{21}\, m^{-3}$.According to the law of mass action,$n_e \cdot n_h = n_i^2$.Therefore,the hole concentration $n_h = \frac{n_i^2}{n_e} = \frac{(10^{16})^2}{10^{21}} = \frac{10^{32}}{10^{21}} = 10^{11}\, m^{-3}$.

In a pure silicon $(n_i = 10^{16}/m^3)$ crystal at $300\, K$,$10^{21}$ atoms of phosphorus are added per cubic meter. The new hole concentration will be

Similar Questions

What are impure semiconductors,doping,and dopants?

If $n_e$ and $v_d$ are the number density of electrons and drift velocity in a semiconductor,respectively,what happens when the temperature is increased?

The electronic configuration of germanium is $2, 8, 18, 4$. To make it an extrinsic semiconductor,a small quantity of antimony is added. What is the nature of the resulting material?

The Bohr radius of the fifth electron of phosphorus (atomic number $Z = 15$) acting as a dopant in silicon (relative dielectric constant $\varepsilon_r = 12$) is ....... $\mathring{A}$.

The rate of recombination or generation of charge carriers in a semiconductor is governed by the law$(s)$ of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module