In a reaction of {C_6H_5Y},the major product | vedclass

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(A) The reaction involves electrophilic aromatic substitution on a substituted benzene ring ${C_6H_5Y}$.Groups that are electron-withdrawing by resona

Vedclass · Accepted Answer

$-COOH$

Vedclass · Answer

(A) The reaction involves electrophilic aromatic substitution on a substituted benzene ring ${C_6H_5Y}$.Groups that are electron-withdrawing by resonance or induction (deactivating groups) are meta-directing.Among the given options,$-COOH$ is an electron-withdrawing group and acts as a meta-directing group.Conversely,$-NH_2$,$-OH$,and $-Cl$ are electron-donating groups (by resonance) and act as ortho/para-directing groups.Therefore,the correct option is $A$.

In a reaction of ${C_6H_5Y}$,the major product $(> 60\%)$ is the $m$-isomer. Therefore,the group $Y$ is:

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